2=1 & 4=5 & 2>3 but how

1^{st} way
ধরি, a=b
কিন্তু,a\ne0 b\ne0
So, a^2=ab
\implies(a+b)(a-b)=b (a-b)
Here is a mistake. Find it.

\fbox{In the second line of the equation,}
\fbox{You can write-}

\implies{(a+a)(a-a)=b(a-a) [a=b]}

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\fbox{Right answer}

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2^{nd} way
We know that ,
Here is a mistake. Find it.

In any inequality, if you divide or multiply both sides with something negative, the < or > will be reversed.In the way to 2nd line from 3rd line, you have divide both sides by log1/2 that is negative. So the sign of > will be reversed. But you haven’t changed it.Here is the mistake.

\fbox {Right answer}