Click here to read the complete problem statement.
Could anyone solve this? don’t give me the answer, I just wanna understand the problem
Well this is basically a pigeonhole principle problem.
You have to maximise number of ducks. => minimise number of repeated cards to make room for more ducks
Now think, when picking 7 boxes, how many boxes do you exclude?
12 - 7 = 5 boxes right? Therefore by PGP, one ducks card must be in at least 5+1=6 boxes to be available to 7 picked boxes. (crux move)
I think that’s enough hint, I’ll let you solve the rest.
@safwanibnnahid you are not allowed to post answer of the problems in the forum. Your response has been suspended.
Your response should have been limited up until giving hints.
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okay warning acknowledged, I have removed the answer, unflag the post now.