The point P, A and B lie in a circle. The point Q lies inside the circle such that
∠PAQ = 90° and PQ = BQ. Prove that
∠AQB - ∠PQA is equal to the arc AB.
Please. Can anyone help me to image a view of this problem?
The point P, A and B lie in a circle. The point Q lies inside the circle such that
∠PAQ = 90° and PQ = BQ. Prove that
∠AQB - ∠PQA is equal to the arc AB.
Please. Can anyone help me to image a view of this problem?