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If I extend the line BC till E and I draw a line perpendicular to the extended BC that will be the height of the BCE triangle right? Let the height be h then the area of BCE will be 1/2 × BC × h right?
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Note that the height of point A and point E from the base BC is same. So the area of both ABC and BCE triangle is 0.5×height×BC , meaning equal area. Now we can solve the problem easily using trigonometry.
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Yeah. I had to assume that the heights are equal. Then I used trig formula for area cause it involves the desired angle…
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Thanks everyone, I just solved it after a whole year 
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That is an achievement!