Shrimp War XXVIII

Schedule

The contest will start on December 6, 2024 at 9:00pm UTC+6:00 and will run for
1 hour  .

Access

It is open for everyone to participate.

Contest Link: Shrimp War XXVIII | Gonitzoggo

The correct answer of problem C should be

AnsC

99

But I don’t know why my submission wasn’t being accepted.
(I’ve checked using Wolframalpha.)

the answer will be 100 you will be putting raw form of it which is N+1

no,
n+1=100
and, n=99
My approach was,
the sum of first n terms is,
\frac{(n+1)^2-1}{(n+1)^2}
You can prove it using induction
\frac{(n+1)^2-1}{(n+1)^2}=\frac{9999}{10000}
\Rightarrow\frac{(n+1)^2-1}{(n+1)^2}=\frac{100^2-1}{100^2}

i also have given the answer as 99 but my answer was rejected… it can also be done analysing the summation pattern